You Really Should Figure This Out Yourself
But I'll assume you've tried. The black lines in the upper right corner
are the two mirrors, and the red lines are the light beam coming in,
reflecting twice and leaving. We want to prove that the incoming
and outgoing light, the two red lines that look parallel, actually are parallel.
Here's one way, that only requires one magic
line to be added to the basic figure: the short black horizontal line is
contructed at right angles to the mirror on the right, where the red light
beam reflects. We've also extended one of the red lines through the mirror:
this is geometry, not physics. Five angles are labeled, A through E. We're going to show
they're all equal.
First, angle A equals angle B, because that's the rule for reflection.
Next, angle C equals angle D, for the same reason.

Angle E equals angle B because they're formed by two crossing lines.
(E plus the big angle is a straight line angle of 180 degrees, and
so is B plus the same big angle equal to the other straight line angle) Hey, this is easy!
Now the trickier one, E = C. You need to remember some geometry for this one.
In particular, when you have two parallel lines and a third line crossing
them, the angles formed are equal. And the reverse: if the angles are
equal, the lines are parallel. The two horizontal black lines are parallel,
since they form equal angles with the vertical black line. (Both are
right angles, since we defined them that way...this is where the fact
that the mirrors are at right angles to each other is used)
Since the two horizontal black lines are parallel, the slanting red line forms
equal angles with them, and angle E equals angle C.
So all the angles are equal, A = B = C = D = E.
Now the final trick! the incoming and outgoing red lines are parallel
because they make equal angles with the other short red line: the
angle with the left red line is A+E, and the angle with the right red line
is C+D, and those are equal since all the labeled angles are equal.
We didn't use any special property of the angle A, so the incoming and
outgoing light is parallel at any value of angle A. We did use
the fact that the mirrors are perpendicular, so this proof is valid only
for a 90 degree corner reflector.
Copyright © 2000 Steve Donnelly
All Rights Reserved.
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